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7n^2+11n-30=0
a = 7; b = 11; c = -30;
Δ = b2-4ac
Δ = 112-4·7·(-30)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-31}{2*7}=\frac{-42}{14} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+31}{2*7}=\frac{20}{14} =1+3/7 $
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